The angular speed of the wheel of a vehicle is increased from 360 rpm to 1200 rpm in 14 second Its angular acceleration is

Question

The angular speed of the wheel of a vehicle is increased from 360 rpm to 1200 rpm in 14 second Its angular acceleration is (A) 2π rad/s2 (B) 28 π rad/s2 (C) 120π rad/s2 (D) 1 rad/s2

Tardigrade Admin · Accepted Answer

beginarrayl ω0=360 rpm =360 × (2 π/60)=12 π rad / s ω=1200 rpm =1200 × (2 π/60)=40 π rad / s text By ω=ω0+α t 40 π=12 π+14(α) α=(28 π/14) α=2 π rad / s 2 endarray

Q. The angular speed of the wheel of a vehicle is increased from $360$ rpm to $1200$ rpm in $14$ second Its angular acceleration is

$2 π r a d / s^{2}$

$28 π r a d / s^{2}$

$120 π r a d / s^{2}$

$1 r a d / s^{2}$

$ω_{0} = 360 r p m = 360 \times \frac{2 π}{60} = 12 π r a d / s ω = 1200 r p m = 1200 \times \frac{2 π}{60} = 40 π r a d / s By ω = ω_{0} + α t 40 π = 12 π + 14 (α) α = \frac{28 π}{14} α = 2 π r a d / s^{2}$

Q. The angular speed of the wheel of a vehicle is increased from 360 rpm to 1200 rpm in 14 second Its angular acceleration is

2πrad/s2

28πrad/s2

120πrad/s2

1rad/s2