Question

The angular speed of seconds needle in a mechanical watch is:

• A. $\pi rad/s$
• B. $\pi \times 30rad/s$
• C. $\frac{\pi }{2}rad/s$
• D. $\frac{\pi }{30}rad/s$

Answer 1

Answer: (D)

$\omega =\frac{2\pi }{T}=\frac{2\times \pi }{60}$
$=\frac{\pi }{30}rad/s$