The angular speed of a motor wheel is increased from 1200 rpm to 3120 rpm in 16 seconds. The angular acceleration of the moto wheel is

Question

The angular speed of a motor wheel is increased from 1200 rpm to 3120 rpm in 16 seconds. The angular acceleration of the moto wheel is (A) 6 π rad / s 2 (B) 8 π rad / s 2 (C) 2 π rad / s 2 (D) 4 π rad / s 2

Tardigrade Admin · Accepted Answer

α=( W 2- W 1/ t )=(2 π n 2-2 π n 1/ t )

Q. The angular speed of a motor wheel is increased from $1200 r p m$ to $3120 r p m$ in $16$ seconds. The angular acceleration of the moto wheel is

$6 π r a d / s^{2}$

$8 π r a d / s^{2}$

$2 π r a d / s^{2}$

$4 π r a d / s^{2}$

$α = \frac{W _{2} - W _{1}}{t} = \frac{2 π n _{2} - 2 π n _{1}}{t}$

Q. The angular speed of a motor wheel is increased from 1200rpm to 3120rpm in 16 seconds. The angular acceleration of the moto wheel is

6πrad/s2

8πrad/s2

2πrad/s2

4πrad/s2