The angle of minimum deviation measured with a prism is 30° and the angle of prism is 60°. The refractive index of prism material is

Question

The angle of minimum deviation measured with a prism is 30° and the angle of prism is 60°. The refractive index of prism material is (A) √2 (B) 2 (C) 3 / 2 (D) 4 / 3

Tardigrade Admin · Accepted Answer

μ=( sin ((A+δm/2))/ sin (A / 2))=( sin 45°/ sin 30°)=√2

Q. The angle of minimum deviation measured with a prism is $3 0^{\circ}$ and the angle of prism is $6 0^{\circ}$ . The refractive index of prism material is

$2$

2

$3/2$

$4/3$

$μ = \frac{s i n ( \frac{A + δ _{m}}{2} )}{s i n ( A /2 )} = \frac{s i n 4 5 ^{\circ}}{s i n 3 0 ^{\circ}} = 2$

Q. The angle of minimum deviation measured with a prism is 30∘ and the angle of prism is 60∘. The refractive index of prism material is

2​

2

3/2

4/3

μ=sin(A/2)sin(2A+δm​​)​=sin30∘sin45∘​=2​

Q. The angle of minimum deviation measured with a prism is $3 0^{\circ}$ and the angle of prism is $6 0^{\circ}$ . The refractive index of prism material is

$2$

$3/2$

$4/3$

$μ = \frac{s i n ( \frac{A + δ _{m}}{2} )}{s i n ( A /2 )} = \frac{s i n 4 5 ^{\circ}}{s i n 3 0 ^{\circ}} = 2$