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Q.
The angle of minimum deviation measured with a prism is $30^{\circ}$ and the angle of prism is $60^{\circ}$. The refractive index of prism material is
Ray Optics and Optical Instruments
Solution:
$\mu=\frac{\sin \left(\frac{A+\delta_{m}}{2}\right)}{\sin (A / 2)}=\frac{\sin 45^{\circ}}{\sin 30^{\circ}}=\sqrt{2}$