The angle of a prism is 42° and refractive index of its material is 3/2 . Then, angle of minimum deviation for this prism is

Question

The angle of a prism is 42° and refractive index of its material is 3/2 . Then, angle of minimum deviation for this prism is (A)  63°  (B)  42°  (C)  28°  (D)  21°

Tardigrade Admin · Accepted Answer

Angle of minimum deviation δ min =(μ-1) A =((3/2)-1) 42° =(1/2) × 42=21°

Q. The angle of a prism is $4 2^{\circ}$ and refractive index of its material is $3/2$ . Then, angle of minimum deviation for this prism is

$6 3^{\circ}$

$4 2^{\circ}$

$2 8^{\circ}$

$2 1^{\circ}$

Angle of minimum deviation
$δ_{m i n} = (μ - 1) A$
$= (\frac{3}{2} - 1) 4 2^{\circ}$
$= \frac{1}{2} \times 42 = 2 1^{\circ}$

Q. The angle of a prism is 42∘ and refractive index of its material is 3/2 . Then, angle of minimum deviation for this prism is

63∘

42∘

28∘

21∘