Question

The angle between the pair of lines $x^2+2xy-y^2=0$

• A. $\frac{\pi }{4}$
• B. $\frac{\pi }{6}$
• C. $\frac{\pi }{2}$
• D. $0$

Answer 1

Answer: (C)

Given pair of lines is $x^2+2xy-y^2=0$
Here, $a=1,b=-1,h=1$
Now, $a+b=1-1=0$
Hence, given pair of lines are perpendicular.