The amplitude of the sinusoidally oscillating electric field of plane wave is 30 (V/M) Then the amplitude of magnetic field is

Question

The amplitude of the sinusoidally oscillating electric field of plane wave is 30 (V/M) Then the amplitude of magnetic field is (A) 2 × 10-9 T (B) 1 × 10-7 T (C) 3 × 109 T (D) 5 × 10-7 T

Tardigrade Admin · Accepted Answer

C=(E0/B0) ⇒ B0=(E0/c) =(30/3 × 108)=10 × 10-8=10-7

Q. The amplitude of the sinusoidally oscillating electric field of plane wave is $30 \frac{V}{M}$ Then the amplitude of magnetic field is

$2 \times 1 0^{- 9} T$

$1 \times 1 0^{- 7} T$

$3 \times 1 0^{9} T$

$5 \times 1 0^{- 7} T$

$C = \frac{E _{0}}{B _{0}} \Rightarrow B_{0} = \frac{E _{0}}{c}$
$= \frac{30}{3 \times 1 0 ^{8}} = 10 \times 1 0^{- 8} = 1 0^{- 7}$

Q. The amplitude of the sinusoidally oscillating electric field of plane wave is 30MV​ Then the amplitude of magnetic field is

2×10−9T

1×10−7T

3×109T

5×10−7T