The amplitude of the electric field of a plane electromagnetic wave in air is 6.0 × 10-4 V m -1. The amplitude of the magnetic field will be

Question

The amplitude of the electric field of a plane electromagnetic wave in air is 6.0 × 10-4 V m -1. The amplitude of the magnetic field will be (A) 1.8 × 105 T (B) 5.0 × 103 T (C) 2.0 × 10-4 T (D) 2.0 × 10-12 T

Tardigrade Admin · Accepted Answer

B0=(E0/c)=(6.0 × 10-4/3 × 108)=2.0 × 10-12 T

Q. The amplitude of the electric field of a plane electromagnetic wave in air is $6.0 \times 1 0^{- 4} V m^{- 1}$ . The amplitude of the magnetic field will be

$1.8 \times 1 0^{5} T$

$5.0 \times 1 0^{3} T$

$2.0 \times 1 0^{- 4} T$

$2.0 \times 1 0^{- 12} T$

$B_{0} = \frac{E _{0}}{c} = \frac{6.0 \times 1 0 ^{- 4}}{3 \times 1 0 ^{8}} = 2.0 \times 1 0^{- 12} T$

Q. The amplitude of the electric field of a plane electromagnetic wave in air is 6.0×10−4Vm−1. The amplitude of the magnetic field will be

1.8×105T

5.0×103T

2.0×10−4T

2.0×10−12T