The amplitude of electric field in a plane electromagnetic wave in vacuum is 9× 10- 3V/m. The amplitude of magnetic field will be

Question

The amplitude of electric field in a plane electromagnetic wave in vacuum is 9× 10- 3V/m. The amplitude of magnetic field will be (A) 3× 10- 11T (B) 3× 105T (C) (1/3)× 10- 11T (D) (1/2 . 7)× 105T

Tardigrade Admin · Accepted Answer

C=(E/B) ⇒ B=(E/C)=(9 × 10- 3/3 × 108)T =3× 10- 11T

Q. The amplitude of electric field in a plane electromagnetic wave in vacuum is $9 \times 1 0^{- 3} V / m .$ The amplitude of magnetic field will be

$3 \times 1 0^{- 11} T$

$3 \times 1 0^{5} T$

$\frac{1}{3} \times 1 0^{- 11} T$

$\frac{1}{2.7} \times 1 0^{5} T$

$C = \frac{E}{B}$
$\Rightarrow B = \frac{E}{C} = \frac{9 \times 1 0 ^{- 3}}{3 \times 1 0 ^{8}} T$
$= 3 \times 1 0^{- 11} T$

Q. The amplitude of electric field in a plane electromagnetic wave in vacuum is 9×10−3V/m. The amplitude of magnetic field will be

3×10−11T

3×105T

31​×10−11T

2.71​×105T