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Q. The amplitude of electric field in a plane electromagnetic wave in vacuum is $9\times 10^{- 3}V/m.$ The amplitude of magnetic field will be

NTA AbhyasNTA Abhyas 2022

Solution:

$C=\frac{E}{B}$
$\Rightarrow B=\frac{E}{C}=\frac{9 \times 10^{- 3}}{3 \times 10^{8}}T$
$=3\times 10^{- 11}T$