The amplification factor of a triode valve is 15. If the grid voltage is changed by 0.3 V, the change in plate voltage in order to keep the current constant (in volt) is:

Question

The amplification factor of a triode valve is 15. If the grid voltage is changed by 0.3 V, the change in plate voltage in order to keep the current constant (in volt) is: (A) 0.02 (B) 0.002 (C) 4.5 (D) 5.0

Tardigrade Admin · Accepted Answer

The ratio of the decrease in plate potential (while grid potential is kept constant) to the increase in grid potential (while plate potential is kept constant) for a definite increase in the plate current is called the amplification factor of the triode valve.

μ = \frac{Δ V _{p}}{Δ V _{g}}

Given,

μ = 15, Δ V_{g} = 0.3 V,

\Rightarrow

Δ V_{p} = μ \times V_{g}

Δ V_{p} = 15 \times 0.3

Δ V_{p} = 4.5 V

μ

has no unit and its value is always greater than one.

Q. The amplification factor of a triode valve is 15. If the grid voltage is changed by 0.3V, the change in plate voltage in order to keep the current constant (in volt) is:

0.02

0.002

4.5

5.0

Q. The amplification factor of a triode valve is $15$ . If the grid voltage is changed by $0.3 V$ , the change in plate voltage in order to keep the current constant (in volt) is: