The amount of work done in increasing the voltage across the plates of the capacitor from 5 V to 10 V is W . The work done in increasing it from 10 V to 15 V will be

Question

The amount of work done in increasing the voltage across the plates of the capacitor from 5 V to 10 V is W . The work done in increasing it from 10 V to 15 V will be (A) W (B) 0.6 W (C) 1.25 W (D) 1.67 W

Tardigrade Admin · Accepted Answer

The work done in increasing the potential is given by W=d U propto(V22-V12) ∴ (W1/W2)=((V22-v12)/(V32-v22)) here V1=5 v, V2=10 V and V3=15 V ∴ (W/W2)+(100-25/225-100)=(75/125) ∴ W2=1.67 W

Q. The amount of work done in increasing the voltage across the plates of the capacitor from $5 V$ to $10 V$ is $W$ . The work done in increasing it from $10 V$ to $15 V$ will be

$W$

$0.6 W$

$1.25 W$

$1.67 W$

Q. The amount of work done in increasing the voltage across the plates of the capacitor from 5V to 10V is W . The work done in increasing it from 10V to 15V will be

W

0.6W

1.25W

1.67W

The work done in increasing the potential is given by W=dU∝(V22​−V12​) ∴W2​W1​​=(V32​−v22​)(V22​−v12​)​ here V1​=5v,V2​=10V and V3​=15V ∴W2​W​+225−100100−25​=12575​ ∴W2​=1.67W

Q. The amount of work done in increasing the voltage across the plates of the capacitor from $5 V$ to $10 V$ is $W$ . The work done in increasing it from $10 V$ to $15 V$ will be

$W$

$0.6 W$

$1.25 W$

$1.67 W$