The amount of heat released when 20 mL of 0.5 M NaOH is mixed with 100 mL of 0.1 M HCl is x kJ. The heat of neutralisation (in kJ mol -1 ) is

Question

The amount of heat released when 20 mL of 0.5 M NaOH is mixed with 100 mL of 0.1 M HCl is x kJ. The heat of neutralisation (in kJ mol -1 ) is (A) -100 x (B) -50 x (C) +100 x (D) +50 x

Tardigrade Admin · Accepted Answer

Equivalents of N a O H=(20 × 0.5/1000)=0.01 Equivalents of H C l=(100 × 0.1/1000)=0.01 0.01 equivalents, of acid and base release heat =-x k J ∴ 1 equivalents of acid and base release heat =(-x/0.0 .1) × 1=-100 x k J

Q. The amount of heat released when $20 m L$ of $0.5 M N a O H$ is mixed with $100 m L$ of $0.1 M H Cl$ is $x k J$ . The heat of neutralisation (in $k J m o l^{- 1}$ ) is

-100 x

-50 x

+100 x

+50 x

Equivalents of $N a O H = \frac{20 \times 0.5}{1000} = 0.01$
Equivalents of $H Cl = \frac{100 \times 0.1}{1000} = 0.01$
$0.01$ equivalents, of acid and base release heat $= - x k J$
$∴ 1$ equivalents of acid and base release heat
$= \frac{- x}{0.0.1} \times 1 = - 100 x k J$

Q. The amount of heat released when 20mL of 0.5MNaOH is mixed with 100mL of 0.1MHCl is xkJ. The heat of neutralisation (in kJmol−1 ) is