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Q. The amount of heat released when $20\, mL$ of $0.5 \,M \,NaOH$ is mixed with $100 \,mL$ of $0.1 \,M \,HCl$ is $x \,kJ$. The heat of neutralisation (in $kJ \,mol ^{-1}$ ) is

BHUBHU 2007

Solution:

Equivalents of $N a O H=\frac{20 \times 0.5}{1000}=0.01$
Equivalents of $H C l=\frac{100 \times 0.1}{1000}=0.01$
$0.01$ equivalents, of acid and base release heat $=-x\, k J$
$\therefore 1$ equivalents of acid and base release heat
$=\frac{-x}{0.0 .1} \times 1=-100\, x\, k J$