The amount of energy required to remove electron from a Li+2 ion in its ground state is how many times greater than the amount of energy needed to remove the electron from an H atom in its ground state ?

Question

The amount of energy required to remove electron from a Li+2 ion in its ground state is how many times greater than the amount of energy needed to remove the electron from an H atom in its ground state ? (A) 9 (B) 6 (C) 4 (D) 5

Tardigrade Admin · Accepted Answer

Ionisation energy of Li +2 text ion =0-(13.6 × (32/12)) =122.4 eV and Ionisation energy of H atom =0-(13.6 × (12/12)) -13.6 eV ∴ I.E. (. of .Li +2)=9 × I.E. (of .H )

Q. The amount of energy required to remove electron from a $L i^{+ 2}$ ion in its ground state is how many times greater than the amount of energy needed to remove the electron from an $H$ atom in its ground state ?

$9$

$6$

$4$

$5$

Ionisation energy of $L i^{+ 2} ion = 0 - (13.6 \times \frac{3 ^{2}}{1 ^{2}})$
$= 122.4 e V$
and Ionisation energy of $H$ atom $= 0 - (13.6 \times \frac{1 ^{2}}{1 ^{2}})$
$- 13.6 e V$
$∴$ I.E. $($ of $L i^{+ 2}) = 9 \times$ I.E. (of $H)$

Q. The amount of energy required to remove electron from a Li+2 ion in its ground state is how many times greater than the amount of energy needed to remove the electron from an H atom in its ground state ?

9

6

4

5

Ionisation energy of Li+2 ion =0−(13.6×1232​) =122.4eV and Ionisation energy of H atom =0−(13.6×1212​) −13.6eV ∴ I.E. ( of Li+2)=9× I.E. (of H)

Q. The amount of energy required to remove electron from a $L i^{+ 2}$ ion in its ground state is how many times greater than the amount of energy needed to remove the electron from an $H$ atom in its ground state ?

$9$

$6$

$4$

$5$

Ionisation energy of $L i^{+ 2} ion = 0 - (13.6 \times \frac{3 ^{2}}{1 ^{2}})$
$= 122.4 e V$
and Ionisation energy of $H$ atom $= 0 - (13.6 \times \frac{1 ^{2}}{1 ^{2}})$
$- 13.6 e V$
$∴$ I.E. $($ of $L i^{+ 2}) = 9 \times$ I.E. (of $H)$