The amount of chlorine evolved by passing 2 A of current in an aqueous solution of NaCl for 30 minutes is

Question

The amount of chlorine evolved by passing 2 A of current in an aqueous solution of NaCl for 30 minutes is (A) 2.64 g (B) 1.32 g (C) 3.62 g (D) 4.22 g

Tardigrade Admin · Accepted Answer

NaCl → Na++Cl- 2Cl-+2e- → Cl2 Q=I× t=2×30×60 =3600 Coulombs 2× 96500 Coulombs produce =71 g of Cl2 3600 Coulombs will produce =(71/2×96500)× 3600 =1.32 g of Cl2

Q. The amount of chlorine evolved by passing $2 A$ of current in an aqueous solution of $N a Cl$ for $30$ minutes is

$2.64 g$

$1.32 g$

$3.62 g$

$4.22 g$

$N a Cl \to N a^{+} + C l^{-}$
$2 C l^{-} + 2 e^{-} \to C l_{2}$
$Q = I \times t = 2 \times 30 \times 60$
$= 3600$ Coulombs
$2 \times 96500$ Coulombs produce $= 71 g$ of $C l_{2}$
$3600$ Coulombs will produce $= \frac{71}{2 \times 96500} \times 3600$
$= 1.32 g$ of $C l_{2}$

Q. The amount of chlorine evolved by passing 2A of current in an aqueous solution of NaCl for 30 minutes is

2.64g

1.32g

3.62g

4.22g