The amount of BaSO 4 formed upon mixing 100 mL of 20.8 % BaCl 2 solution with 50 mL of 9.8 % H 2 SO 4 solution will be: ( Ba =137, Cl =35.5, S =32, H =1 and O =16)

Question

The amount of BaSO 4 formed upon mixing 100 mL of 20.8 % BaCl 2 solution with 50 mL of 9.8 % H 2 SO 4 solution will be: ( Ba =137, Cl =35.5, S =32, H =1 and O =16) (A) 23.3 g (B) 11.65 g (C) 30.6 g (D) 33.2 g

Tardigrade Admin · Accepted Answer

Q. The amount of BaSO4​ formed upon mixing 100mL of 20.8%BaCl2​ solution with 50mL of 9.8%H2​SO4​ solution will be : (Ba=137,Cl=35.5,S=32,H=1 and O=16)

23.3 g

11.65 g

30.6 g

33.2 g

Q. The amount of $B a S O_{4}$ formed upon mixing $100 m L$ of $20.8% B a C l_{2}$ solution with $50 m L$ of $9.8% H_{2} S O_{4}$ solution will be : $(B a = 137, Cl = 35.5, S = 32, H = 1$ and $O = 16)$