The amount (in grams) of potassium dichromate (MW = 294) present in 75 mL of 0.16 M aqueous solution is

Question

The amount (in grams) of potassium dichromate (MW = 294) present in 75 mL of 0.16 M aqueous solution is (A) 0.040 grams (B) 2.450 grams (C) 3.000 grams (D) 3.528 grams

Tardigrade Admin · Accepted Answer

Molar mass of K2Cr2O7 is 294 g/ mol. Amount of K2Cr2O7 present = 0.16 × 0.075 × 294 = 3.528 grams

Q. The amount (in grams) of potassium dichromate $(M W = 294)$ present in $75 m L$ of $0.16 M$ aqueous solution is

0.040 grams

2.450 grams

3.000 grams

3.528 grams

Molar mass of $K_{2} C r_{2} O_{7}$ is $294 g / m o l$ .
Amount of $K_{2} C r_{2} O_{7}$ present $= 0.16 \times 0.075 \times 294$
$= 3.528$ grams

Q. The amount (in grams) of potassium dichromate (MW=294) present in 75mL of 0.16M aqueous solution is