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Q. The amount (in grams) of potassium dichromate $(MW = 294)$ present in $75 \,mL$ of $0.16 \,M$ aqueous solution is

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Solution:

Molar mass of $K_2Cr_2O_7$ is $294 \,g/ mol$.
Amount of $K_2Cr_2O_7$ present $= 0.16 \times 0.075 \times 294$
$= 3.528$ grams