The amine formed from an amide by means of bromine and alkali has

Question

The amine formed from an amide by means of bromine and alkali has (A) Same number of C atoms as that of amide (B) One less C atom than that of amide (C) One more C atom than that of amide (D) Two more C atoms than that of amide

Tardigrade Admin · Accepted Answer

underset(2c)CH3 - CO - NH2 xrightarrow[ textHofmann's bromamide]NaOH/Br2 underset(IC)CH3- NH2

Q. The amine formed from an amide by means of bromine and alkali has

Same number of $C$ atoms as that of amide

One less $C$ atom than that of amide

One more $C$ atom than that of amide

Two more $C$ atoms than that of amide

$(2 c) C H_{3} - CO - N H_{2} N a O H / B r_{2} Hofmann’s bromamide (I C) C H_{3} - N H_{2}$

Q. The amine formed from an amide by means of bromine and alkali has

Same number of C atoms as that of amide

One less C atom than that of amide

One more C atom than that of amide

Two more C atoms than that of amide

(2c)CH3​−CO−NH2​​NaOH/Br2​Hofmann’s bromamide​(IC)CH3​−NH2​​

Same number of $C$ atoms as that of amide

One less $C$ atom than that of amide

One more $C$ atom than that of amide

Two more $C$ atoms than that of amide

$(2 c) C H_{3} - CO - N H_{2} N a O H / B r_{2} Hofmann’s bromamide (I C) C H_{3} - N H_{2}$