The adjoining figure shows a spherical Gaussian surface and a charge distribution. When calculating the flux of electric field through the Gaussian surface, the electric field will be due to

Question

The adjoining figure shows a spherical Gaussian surface and a charge distribution. When calculating the flux of electric field through the Gaussian surface, the electric field will be due to (A) +q3 alone (B) +q1 and +q3 (C) +q1,-q2 and +q3 (D) +q1 and -q2

Tardigrade Admin · Accepted Answer

At any point over the spherical Gaussian surface, net electric field is the vector sum of electric fields due to +q1, -q2 and +q3

Q. The adjoining figure shows a spherical Gaussian surface and a charge distribution. When calculating the flux of electric field through the Gaussian surface, the electric field will be due to

$+ q_{3}$ alone

$+ q_{1}$ and $+ q_{3}$

$+ q_{1}, - q_{2}$ and $+ q_{3}$

$+ q_{1}$ and $- q_{2}$

At any point over the spherical Gaussian surface, net electric field is the vector sum of electric fields due to $+ q_{1}$ , $- q_{2}$ and $+ q_{3}$

Q. The adjoining figure shows a spherical Gaussian surface and a charge distribution. When calculating the flux of electric field through the Gaussian surface, the electric field will be due to

+q3​ alone

+q1​ and +q3​

+q1​,−q2​ and +q3​

+q1​ and −q2​

At any point over the spherical Gaussian surface, net electric field is the vector sum of electric fields due to +q1​, −q2​ and +q3​

$+ q_{3}$ alone

$+ q_{1}$ and $+ q_{3}$

$+ q_{1}, - q_{2}$ and $+ q_{3}$

$+ q_{1}$ and $- q_{2}$

At any point over the spherical Gaussian surface, net electric field is the vector sum of electric fields due to $+ q_{1}$ , $- q_{2}$ and $+ q_{3}$