The acute angle (θ) between lines L1 and L2 with slopes m1 and m2 respectively is given by

Question

The acute angle (θ) between lines L1 and L2 with slopes m1 and m2 respectively is given by (A)  tan θ=(m1-m2/1+m1 m2), as 1+m1 m2 ≠ 0 (B)  tan θ=(m2-m1/1+m1 m2), as 1+m1 m2 ≠ 0 (C)  tan θ=|(m2-m1/1+m1 m2)|, as 1+m1 m2 ≠ 0 (D) None of the above

Tardigrade Admin · Accepted Answer

The acute angle (say θ ) between lines L1 and L2 with slopes m1 and m2 respectively, is given by tan θ=|(m2-m1/1+m1 m2)| text , as 1+m1 m2 ≠ 0

Q. The acute angle $(θ)$ between lines $L_{1}$ and $L_{2}$ with slopes $m_{1}$ and $m_{2}$ respectively is given by

$tan θ = \frac{m _{1} - m _{2}}{1 + m _{1} m _{2}}$ , as $1 + m_{1} m_{2} \neq = 0$

$tan θ = \frac{m _{2} - m _{1}}{1 + m _{1} m _{2}}$ , as $1 + m_{1} m_{2} \neq = 0$

$tan θ = ∣ ∣ \frac{m _{2} - m _{1}}{1 + m _{1} m _{2}} ∣ ∣$ , as $1 + m_{1} m_{2} \neq = 0$

None of the above

The acute angle (say $θ$ ) between lines $L_{1}$ and $L_{2}$ with slopes $m_{1}$ and $m_{2}$ respectively, is given by
$tan θ = ∣ ∣ \frac{m _{2} - m _{1}}{1 + m _{1} m _{2}} ∣ ∣, as 1 + m_{1} m_{2} \neq = 0$

Q. The acute angle (θ) between lines L1​ and L2​ with slopes m1​ and m2​ respectively is given by

tanθ=1+m1​m2​m1​−m2​​, as 1+m1​m2​=0

tanθ=1+m1​m2​m2​−m1​​, as 1+m1​m2​=0

tanθ=∣∣​1+m1​m2​m2​−m1​​∣∣​, as 1+m1​m2​=0