The activation energy of exothermic reaction A→ B is 80 text kJ text mol-1 . The heat of reaction is 200 text kJ text mol-1 . The activation energy for the reaction B→ A (in text kJ text mol-1) will be

Question

The activation energy of exothermic reaction A→ B is 80 text kJ text mol-1 . The heat of reaction is 200 text kJ text mol-1 . The activation energy for the reaction B→ A (in text kJ text mol-1) will be (A) 80 (B) 120 (C) 40 (D) 200

Tardigrade Admin · Accepted Answer

Ea (activation energy) (A→ B)=80 text kJ text mol-1 Heat of reaction (A→ B)=200 text kJ text mol-1 for (B→ A) backward reaction Ea(B→ A)=Ea(A→ B)+ heat of reaction =80+200=280 kJ mol-1

Q. The activation energy of exothermic reaction $A \to B$ is $80 k J m o l^{- 1}$ . The heat of reaction is $200 k J m o l^{- 1}$ . The activation energy for the reaction $B \to A$ $(in k J m o l^{- 1})$ will be

80

120

40

200

280

$E_{a}$ (activation energy) $(A \to B) = 80 k J m o l^{- 1}$
Heat of reaction $(A \to B) = 200 k J m o l^{- 1}$
for $(B \to A)$ backward reaction
$E_{a} (B \to A) = E_{a} (A \to B) +$ heat of reaction $< b r / >= 80 + 200 = 280 k J m o l^{- 1}$

Q. The activation energy of exothermic reaction A→B is 80kJmol−1 . The heat of reaction is 200kJmol−1 . The activation energy for the reaction B→A (inkJmol−1) will be

80

120

40

200

280

Ea​ (activation energy) (A→B)=80kJmol−1 Heat of reaction (A→B)=200kJmol−1 for (B→A) backward reaction Ea​(B→A)=Ea​(A→B)+ heat of reaction <br/>=80+200=280kJmol−1

Q. The activation energy of exothermic reaction $A \to B$ is $80 k J m o l^{- 1}$ . The heat of reaction is $200 k J m o l^{- 1}$ . The activation energy for the reaction $B \to A$ $(in k J m o l^{- 1})$ will be

$E_{a}$ (activation energy) $(A \to B) = 80 k J m o l^{- 1}$
Heat of reaction $(A \to B) = 200 k J m o l^{- 1}$
for $(B \to A)$ backward reaction
$E_{a} (B \to A) = E_{a} (A \to B) +$ heat of reaction $< b r / >= 80 + 200 = 280 k J m o l^{- 1}$