The activation energy of a reaction can be determined from the slope of which of the following graphs?

Question

The activation energy of a reaction can be determined from the slope of which of the following graphs? (A)  textIn K vs ⋅ (1/ T ) (B) ( T / textIn K ) textVS (1/ T ) (C)  textIn K vs ⋅ T (D) ( textIn K / T ) vs ⋅ T

Tardigrade Admin · Accepted Answer

Arrhenius equation K = A ⋅ e - Ea / RT ⇒ ℓ textnK=ℓ textnA-( Ea / RT ) so, activation energy of reaction can be determined from the slope of ℓ n K vs (1/T)

Q. The activation energy of a reaction can be determined from the slope of which of the following graphs?

$In K$ vs $\cdot \frac{1}{T}$

$\frac{T}{In K} VS \frac{1}{T}$

$In K v s \cdot T$

$\frac{In K}{T} v s \cdot T$

Arrhenius equation
$K = A \cdot e^{- E a / RT} \Rightarrow ℓ nK = ℓ n A - \frac{E a}{RT}$
so, activation energy of reaction can be determined from the slope of $ℓ n K v s \frac{1}{T}$

Q. The activation energy of a reaction can be determined from the slope of which of the following graphs?

InK vs ⋅T1​

InKT​VST1​

InKvs⋅T

TIn K ​vs⋅T

Arrhenius equation K=A⋅e−Ea/RT⇒ℓnK=ℓnA−RTEa​ so, activation energy of reaction can be determined from the slope of ℓnKvsT1​

$In K$ vs $\cdot \frac{1}{T}$

$\frac{T}{In K} VS \frac{1}{T}$

$In K v s \cdot T$

$\frac{In K}{T} v s \cdot T$

Arrhenius equation
$K = A \cdot e^{- E a / RT} \Rightarrow ℓ nK = ℓ n A - \frac{E a}{RT}$
so, activation energy of reaction can be determined from the slope of $ℓ n K v s \frac{1}{T}$