The acidic strength of substituted carboxylic acid is known to depend on nature and position of substituents. In the following examples, an attempt has been made to arrange the acids in decreasing order of acidic strength. Which one of the series is incorrect?

Question

The acidic strength of substituted carboxylic acid is known to depend on nature and position of substituents. In the following examples, an attempt has been made to arrange the acids in decreasing order of acidic strength. Which one of the series is incorrect? (A) O 2 NCH 2 COOH > HOCH 2 COOH > CH 3 COOH > CH 2 BrCOOH (B) Cl 3 CCOOH > FCH 2 COOH > Cl 2 CHCOOH > CH 2 BrCOOH (C) CH 3 CH 2 CHClCOOH > CH 3 CHClCH 2 COOH > CH 3 CH 2 CH 2 COOH > CH 3 CH ( CH 3) CH 2 COOH (D) CH 3 COOH > CH 3 CH 2 COOH >( CH 3)2 CHCOOH > ( CH 3)3 CCOOH

Tardigrade Admin · Accepted Answer

Two Cl from same positions gives greater -I -effect than a single F from the same position hence. Cl 2 CHCOOH is stronger acid than FCH 2 COOH .

Q. The acidic strength of substituted carboxylic acid is known to depend on nature and position of substituents. In the following examples, an attempt has been made to arrange the acids in decreasing order of acidic strength. Which one of the series is incorrect?

$O_{2} NC H_{2} COO H > H OC H_{2} COO H > C H_{3} COO H > C H_{2} B r COO H$

$C l_{3} CCOO H > FC H_{2} COO H > C l_{2} C H COO H > C H_{2} B r COO H$

$C H_{3} C H_{2} C H ClCOO H > C H_{3} C H ClC H_{2} COO H > C H_{3} C H_{2} C H_{2} COO H > C H_{3} C H (C H_{3}) C H_{2} COO H$

$C H_{3} COO H > C H_{3} C H_{2} COO H > (C H_{3})_{2} C H COO H > (C H_{3})_{3} CCOO H$

Two $Cl$ from same positions gives greater $- I$ -effect than a single $F$ from the same position hence.

$C l_{2} C H COO H$ is stronger acid than $FC H_{2} COO H .$

Q. The acidic strength of substituted carboxylic acid is known to depend on nature and position of substituents. In the following examples, an attempt has been made to arrange the acids in decreasing order of acidic strength. Which one of the series is incorrect?

O2​NCH2​COOH>HOCH2​COOH>CH3​COOH>CH2​BrCOOH

Cl3​CCOOH>FCH2​COOH>Cl2​CHCOOH>CH2​BrCOOH

CH3​CH2​CHClCOOH>CH3​CHClCH2​COOH>CH3​CH2​CH2​COOH>CH3​CH(CH3​)CH2​COOH

CH3​COOH>CH3​CH2​COOH>(CH3​)2​CHCOOH>(CH3​)3​CCOOH

Two Cl from same positions gives greater −I -effect than a single F from the same position hence. Cl2​CHCOOH is stronger acid than FCH2​COOH.

$O_{2} NC H_{2} COO H > H OC H_{2} COO H > C H_{3} COO H > C H_{2} B r COO H$

$C l_{3} CCOO H > FC H_{2} COO H > C l_{2} C H COO H > C H_{2} B r COO H$

$C H_{3} C H_{2} C H ClCOO H > C H_{3} C H ClC H_{2} COO H > C H_{3} C H_{2} C H_{2} COO H > C H_{3} C H (C H_{3}) C H_{2} COO H$

$C H_{3} COO H > C H_{3} C H_{2} COO H > (C H_{3})_{2} C H COO H > (C H_{3})_{3} CCOO H$

Two $Cl$ from same positions gives greater $- I$ -effect than a single $F$ from the same position hence.

$C l_{2} C H COO H$ is stronger acid than $FC H_{2} COO H .$