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Question
Mathematics
The 6th term of an A.P. is 18 and the 9th term is 12. The 15th term is equal to
Q. The
6
t
h
term of an
A
.
P
. is
18
and the
9
t
h
term is
12
. The
1
5
t
h
term is equal to
3282
181
Sequences and Series
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A
0
56%
B
1
16%
C
2
18%
D
3
10%
Solution:
Let
a
be the first term and
d
be the common difference.
∴
a
6
=
18
⇒
a
+
5
d
=
18
....
(
i
)
a
9
=
12
⇒
a
+
8
d
=
12
...
(
ii
)
Solving
(
i
)
and
(
ii
)
, we get
a
=
28
,
d
=
−
2
∴
a
15
=
a
+
14
d
=
28
+
14
(
−
2
)
=
0