Question

The $30^{th}$ term of the arithmetic progression $10,7,4$ is

• A. -97
• B. -87
• C. -77
• D. -67
• E. -57

Answer 1

Answer: (C)

We have, $10,7,4,\dots \dots$
which is an $A.P$.
$\therefore a=10,d=-3$
$\therefore a_{30}=a+29d\left[\because a_n=a+(n-1)d\right]$
$=10+29(-3)$
$=10-87$
$=-77$