Tardigrade
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Tardigrade
Question
Chemistry
Tertiary alkyl halide is practically inert to substitution by SN2 mechanism because of
Q. Tertiary alkyl halide is practically inert to substitution by
S
N
2
mechanism because of
3981
244
KCET
KCET 2018
Haloalkanes and Haloarenes
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A
Insolubility
7%
B
Instability
9%
C
Inductive effect
16%
D
Steric hindrance
69%
Solution:
In tertiary alkyl halides steric hindrance does not allow substitution by
S
N
2
mechanism in which the nucleophile attacks on the carbon atom and the reaction takes place in single step.