Ten moles of an ideal gas at constant temperature 600 K is compressed from 100 L to 10 L. The work done in the process is

Question

Ten moles of an ideal gas at constant temperature 600 K is compressed from 100 L to 10 L. The work done in the process is (A)  4.11× 104 J  (B)  -4.11× 104 J  (C)  11.4× 104 J  (D)  -11.4× 104 J

Tardigrade Admin · Accepted Answer

Work done in an isothermal process W =2.3026 n R T log 10((V2/V1)) =2.3026 × 10 × 8.3 × 600 log 10((10/100)) =-11.4 × 104 J

Q. Ten moles of an ideal gas at constant temperature $600 K$ is compressed from $100 L$ to $10 L$ . The work done in the process is

$4.11 \times 1 0^{4} J$

$- 4.11 \times 1 0^{4} J$

$11.4 \times 1 0^{4} J$

$- 11.4 \times 1 0^{4} J$

Work done in an isothermal process
$W = 2.3026 n RT lo g_{10} (\frac{V _{2}}{V _{1}})$
$= 2.3026 \times 10 \times 8.3 \times 600 lo g_{10} (\frac{10}{100})$
$= - 11.4 \times 1 0^{4} J$

Q. Ten moles of an ideal gas at constant temperature 600K is compressed from 100L to 10L. The work done in the process is

4.11×104J

−4.11×104J

11.4×104J

−11.4×104J