Taylor is heterozygous for two autosomal gene pair (CcDd). He is also colour-blind. What is the probability of gametes having c, d and colour-blind genes?

Question

Taylor is heterozygous for two autosomal gene pair (CcDd). He is also colour-blind. What is the probability of gametes having c, d and colour-blind genes? (A) (1/2) (B) (1/4) (C) (1/8) (D) (1/16)

Tardigrade Admin · Accepted Answer

The genotype of Taylor would be: CcDdXcy - Taylor Gametes=cdXc=(1/2)× (1/2)× (1/2) =(1/8)

Q. Taylor is heterozygous for two autosomal gene pair (CcDd). He is also colour-blind. What is the probability of gametes having c, d and colour-blind genes?

$\frac{1}{2}$

$\frac{1}{4}$

$\frac{1}{8}$

$\frac{1}{16}$

The genotype of Taylor would be:
CcDdX^cy - Taylor
$G am e t es = c d X^{c} = \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2}$
$= \frac{1}{8}$