Question

${\tanh }^{-1}x$ is equal to

• A. $2\log \frac{1-x}{1+x}$
• B. $2\log \frac{1+x}{1-x}$
• C. $\frac{1}{2}\log \frac{1+x}{1-x}$
• D. $\frac{1}{2}\log \frac{1-x}{1+x}$

Answer 1

Answer: (C)

${\tanh }^{-1}x=\frac{1}{2}\log \frac{1+x}{1-x}$