tan 25Â° = p ⇒ : (tan 245Â° + tan 335Â° / tan 205Â° - tan 115Â°) =

Question

tan 25Â° = p ⇒ : (tan 245Â° + tan 335Â° / tan 205Â° - tan 115Â°) =  (A) (p2 -1/p2 +1) (B) (p2 + 1 /p2 - 1) (C) (1 - p2 /1 + p2 ) (D) ( 1 + p2 /1 - p2 )

Tardigrade Admin · Accepted Answer

tan (245°) = tan (270° - 25°) tan (335°) = tan (360° -25°) tan (205°) = tan (180° + 25°) tan (115°) = tan (90° + 25°)

Q. $tan 25° = p \Rightarrow \frac{t an 245° + t a n 335°}{t a n 205° - t a n 115°} =$

$\frac{p ^{2} - 1}{p ^{2} + 1}$

$\frac{p ^{2} + 1}{p ^{2} - 1}$

$\frac{1 - p ^{2}}{1 + p ^{2}}$

$\frac{1 + p ^{2}}{1 - p ^{2}}$

$tan (245°) = tan (270° - 25°)$
$tan (335°) = tan (360° - 25°)$
$tan (205°) = tan (180° + 25°)$
$tan (115°) = tan (90° + 25°)$

Q. tan25°=p⇒tan205°−tan115°tan245°+tan335°​=

p2+1p2−1​

p2−1p2+1​

1+p21−p2​

1−p21+p2​