Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
tan 25° = p ⇒ : (tan 245° + tan 335° / tan 205° - tan 115°) =
Q.
tan
25°
=
p
⇒
t
a
n
205°
−
t
a
n
115°
t
an
245°
+
t
a
n
335°
=
3384
232
Trigonometric Functions
Report Error
A
p
2
+
1
p
2
−
1
14%
B
p
2
−
1
p
2
+
1
29%
C
1
+
p
2
1
−
p
2
42%
D
1
−
p
2
1
+
p
2
15%
Solution:
tan
(
245°
)
=
tan
(
270°
−
25°
)
tan
(
335°
)
=
tan
(
360°
−
25°
)
tan
(
205°
)
=
tan
(
180°
+
25°
)
tan
(
115°
)
=
tan
(
90°
+
25°
)