Switch S is closed at t=0 . After sufficiently long time, an iron rod is inserted into the inductor L. Then, the light bulb

Question

Switch S is closed at t=0 . After sufficiently long time, an iron rod is inserted into the inductor L. Then, the light bulb (A) glows more brightly (B) gets dimmer (C) glows with the same brightness (D) gets momentarily dimmer and then glows more brightly

Tardigrade Admin · Accepted Answer

As the rod is inserted, inductance increases and hence the voltage across inductor increases. This causes a drop in the voltage across the bulb and hence it gets dimmer.

Q. Switch S is closed at t=0. After sufficiently long time, an iron rod is inserted into the inductor L. Then, the light bulb

glows more brightly

gets dimmer

glows with the same brightness

gets momentarily dimmer and then glows more brightly

As the rod is inserted, inductance increases and hence the voltage across inductor increases. This causes a drop in the voltage across the bulb and hence it gets dimmer.

Q. Switch $S$ is closed at $t = 0.$ After sufficiently long time, an iron rod is inserted into the inductor $L$ . Then, the light bulb