Surface tension of the liquid is S. Work done in increasing the radius of soap bubble from R to 3R at given temperature will be

Question

Surface tension of the liquid is S. Work done in increasing the radius of soap bubble from R to 3R at given temperature will be (A) 8π SR2 (B) 16π SR2 (C) 64π SR2 (D) (18π SR2/3)

Tardigrade Admin · Accepted Answer

Given, surface tension of the liquid is

S

.
Work done in blowing a soap bubble. So as to increase its radius from

R_{1} = R

to

R_{2} = 3 R

is given by

W = S \cdot 8 π [R_{2}^{2} - R_{1}^{2}]

where

S =

surface tension

W = S \cdot 8 π [(3 R)^{2} - (R)^{2}]

= S \cdot 8 π [9 R^{2} - R^{2}]

= S \cdot 8 π \cdot 8 R^{2} = 64 π R^{2} S .

Q. Surface tension of the liquid is $S$ . Work done in increasing the radius of soap bubble from $R$ to $3 R$ at given temperature will be

$8 π S R^{2}$

$16 π S R^{2}$

$64 π S R^{2}$

$\frac{18 π S R ^{2}}{3}$

Q. Surface tension of the liquid is S. Work done in increasing the radius of soap bubble from R to 3R at given temperature will be

8πSR2

16πSR2

64πSR2

318πSR2​

Given, surface tension of the liquid is S. Work done in blowing a soap bubble. So as to increase its radius from R1​=R to R2​=3R is given by W=S⋅8π[R22​−R12​] where S= surface tension W=S⋅8π[(3R)2−(R)2] =S⋅8π[9R2−R2] =S⋅8π⋅8R2=64πR2S.

Q. Surface tension of the liquid is $S$ . Work done in increasing the radius of soap bubble from $R$ to $3 R$ at given temperature will be

$8 π S R^{2}$

$16 π S R^{2}$

$64 π S R^{2}$

$\frac{18 π S R ^{2}}{3}$