Surface tension of mercury is 0.465 N m-1 . The excess pressure inside a mercury drop of diameter 6 mm is

Question

Surface tension of mercury is 0.465 N m-1 . The excess pressure inside a mercury drop of diameter 6 mm is (A)  310 pa  (B)  410 pa  (C)  510 pa  (D)  610 pa

Tardigrade Admin · Accepted Answer

Here, D = 6 mm r=(D/2)=(6 mm/2)=3 mm=3×10-3 m Excess pressure inside the mercury drop is P=(2S/r)=(2×0.465 N m-1/3×10-3 m) = 310 Pa

Q. Surface tension of mercury is $0.465 N m^{- 1}$ . The excess pressure inside a mercury drop of diameter $6 mm$ is

$310 p a$

$410 p a$

$510 p a$

$610 p a$

Here, $D = 6 mm$
$r = \frac{D}{2} = \frac{6 mm}{2} = 3 mm = 3 \times 1 0^{- 3} m$
Excess pressure inside the mercury drop is
$P = \frac{2 S}{r} = \frac{2 \times 0.465 N m ^{- 1}}{3 \times 1 0 ^{- 3} m}$
$= 310 P a$

Q. Surface tension of mercury is 0.465Nm−1 . The excess pressure inside a mercury drop of diameter 6mm is

310pa

410pa

510pa

610pa