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Question
Mathematics
Suppose x and y are real numbers satisfying the equation x2+y2-22 x-20 y+221=0. The value of x y is
Q. Suppose
x
and
y
are real numbers satisfying the equation
x
2
+
y
2
−
22
x
−
20
y
+
221
=
0
. The value of
x
y
is
156
109
Complex Numbers and Quadratic Equations
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A
90
B
100
C
110
D
none
Solution:
(
x
−
11
)
2
+
(
y
−
10
)
2
=
0
⇒
x
=
11
and
y
=
10
⇒
x
y
=
110