Suppose x and y are real numbers satisfying the equation x2+y2-22 x-20 y+221=0. The value of x y is

Question

Suppose x and y are real numbers satisfying the equation x2+y2-22 x-20 y+221=0. The value of x y is (A) 90 (B) 100 (C) 110 (D) none

Tardigrade Admin · Accepted Answer

( x -11)2+( y -10)2=0 ⇒ x = 11 text and y =10 ⇒ xy =110

Q. Suppose $x$ and $y$ are real numbers satisfying the equation $x^{2} + y^{2} - 22 x - 20 y + 221 = 0$ . The value of $x y$ is