Q.
Suppose that z1,z2,z3 are three vertices of an equilateral triangle in the Argand plane. Let α=21(3+i) and β be a non-zero complex number. The points αz1+β,αz2+β,αz3+β will be
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WBJEEWBJEE 2014Complex Numbers and Quadratic Equations
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Solution:
Since, z1,z2 and z3 are the vertices of an equilateral triangle, therefore ∣z1−z2∣=∣z2−z3∣ =∣z3−z1∣=k (say)
Also, α=21(3+i) ⇒∣α∣=213+1=21×2=1
Let A=αz1+β,B=αz2+β
and C=αz3+β
Now, ∣AB∣=∣αz2+β−(αz1+β)∣ =∣α(z2−z1)∣ =∣α∣∣z2−z1∣ =∣1∣∣z2−z1∣ =1∣z2−z1∣ =∣z2−z1∣=k
Similarly, BC=CA=k
Hence, the points αz1+β,αz2+β and αz3+β are the vertices of an equilateral triangle.