Q.
Suppose that A and B form the compounds B2A3 and B2A. If 0.05 mole of B2A3 weighs 9g and 0.1 mole of B2A weighs 10g, the atomic weight of A and B respectively are
2765
195
Some Basic Concepts of Chemistry
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Solution:
Let the atomic mass of B=yg;A=xg lnB2A3 2y+3x= mol. mass of B2A3= mole given weight 2y+3x=0.059g
In B2A ∴2y+x=0.110g
Solving x and y {x=40y=30}