Q.
Suppose 10000 tickets are sold in a lottery each for ₹1. First prize is of ₹3000 and the second prize is of ₹2000. There are three third prizes of ₹500 each. If you buy one ticket, then your expectation is
Let X denote the random variable of the prizes. ∴X can take values 3000,2000,500 P(X=3000)=100001 P(X−2000)=100001\ P(X=500)=100003
Now, E(X)=ΣXP(X) =3000×100001+2000×100001+500×100003 =100003000+2000+1500 =100006500=0.65