Question

Sumita is twice as old as Ashima. If 6 years is subtracted from Ashima's age and 4 years added to Sumita's age than Sumita will be four times that of Ashima's age. Then their ages are

• A. 14
• B. 28
• C. 12
• D. 26

Answer 1

Answer: (C), (D)

Let Ashima's present age be $x$ years and Sumita's present age be y years From question
$y=2x$....(i)
Also,
$(y+4)=4(x-6)$
$\therefore 2x+4=4x-24$
$\text{ [From (i) }y=2x\text{ ] }$
$\therefore 2x=28$
$\therefore x=14$
$\text{ And }\mathrm{y}=28$
$\therefore 2\text{ years ago, Ashima’s age }=x-2=12\text{ years }$
$2\text{ years ago Sunita’s age }=y-2$
$=28-2$
$=26\text{ years }$