Question

Sulphur reacts with chlorine in $1:2$ ratio and forms $X$. Hydrolysis of $X$ gives a sulphur compound $Y$. What is the structure and hybridisation of anion of $Y$ ?

• A. tetrahedral, $s{p}^3$
• B. linear, $sp$
• C. pyramidal, $s{p}^3$
• D. trigonal planar, $s{p}^2$

Answer 1

Answer: (C)

When sulphur reacts with chlorine in $1:2$ ratio, then $SC{l}_4$ is obtained which on hydrolysis gives sulphurous acid $\left(H_{2}S{O}_3\right)$.
$\underset{1}{S}+\underset{2}{2C{l}_2}\to \underset{(X)}{SC{l}_4}$
$SC{l}_4+4H_{2}O\to S(OH{)}_4+4HCl$
$S(OH{)}_4\to \underset{\text{sulphurous acid (Y)}}{H_{2}S{O}_3}+H_{2}O$
The anion of $(Y)$ is $S{O}_3^{2-}$.