1. Tardigrade
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  3. Chemistry
  4. Sulphur reacts with chlorine in 1: 2 ratio and forms X. Hydrolysis of X gives a sulphur compound Y. What is the structure and hybridisation of anion of Y ?

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Q. Sulphur reacts with chlorine in $1: 2$ ratio and forms $X$. Hydrolysis of $X$ gives a sulphur compound $Y$. What is the structure and hybridisation of anion of $Y$ ?

AIIMSAIIMS 2008

Solution:

When sulphur reacts with chlorine in $1: 2$ ratio, then $SCl _{4}$ is obtained which on hydrolysis gives sulphurous acid $\left( H _{2} SO _{3}\right)$.
$\underset{1}{S} + \underset{2}{2Cl_2} \to \underset{(X)}{SCl_4}$
$SCl_4 + 4H_2O \to S(OH)_4 + 4HCl$
$S(OH)_4 \to \underset{\text{sulphurous acid (Y)}}{H_2SO_3} + H_2O$
The anion of $(Y)$ is $SO _{3}^{2-}$.
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