Study the following table Compound (mol. mass) Mass of the compound (in gram) taken I. CO2(.44.) 4.4 II. NO2(.46.) 2.3 III. H2O2(.34.) 6.8 IV. SO2(.64.) 1.6 Which two compounds have least mass of oxygen?

Question

Study the following table Compound (mol. mass) Mass of the compound (in gram) taken I. CO2(.44.) 4.4 II. NO2(.46.) 2.3 III. H2O2(.34.) 6.8 IV. SO2(.64.) 1.6 Which two compounds have least mass of oxygen? (A) II and IV (B) I and III (C) I and II (D) III and IV

Tardigrade Admin · Accepted Answer

Mass of oxygen present =(w t . o f C o m p o u n d/M o l . w t . o f c o m p o u n d)× 32 I. Mass of oxygen present =(4.4/44)× 32=3.2g II. Mass of oxygen present =(2.3/46)× 32=1.6g III. Mass of oxygen present =(6.8/34)× 32=6.4g IV. Mass of oxygen present =(1.6/64)× 32=0.8g So II and IV have least mass of oxygen.

	Compound (mol. mass)	Mass of the compound (in gram) taken
$I .$	$C O_{2} (44)$	4.4
$II .$	$N O_{2} (46)$	2.3
$III .$	$H_{2} O_{2} (34)$	6.8
$I V .$	$S O_{2} (64)$	1.6

Q. Study the following table Compound (mol. mass) Mass of the compound (in gram) taken I. CO2​(44) 4.4 II. NO2​(46) 2.3 III. H2​O2​(34) 6.8 IV. SO2​(64) 1.6 Which two compounds have least mass of oxygen?

II and IV

I and III

I and II

III and IV

Mass of oxygen present =Mol.wt.ofcompoundwt.ofCompound​×32 I. Mass of oxygen present =444.4​×32=3.2g II. Mass of oxygen present =462.3​×32=1.6g III. Mass of oxygen present =346.8​×32=6.4g IV. Mass of oxygen present =641.6​×32=0.8g So II and IV have least mass of oxygen.

Q. Study the following table

Compound (mol. mass) Mass of the compound (in gram) taken

$I .$ $C O_{2} (44)$ 4.4

$II .$ $N O_{2} (46)$ 2.3

$III .$ $H_{2} O_{2} (34)$ 6.8

$I V .$ $S O_{2} (64)$ 1.6

Which two compounds have least mass of oxygen?