Question

Statement I Points $(-4,6,10),(2,4,6)$ and $(14,0,-2)$ are collinear.
Statement II Point $(14,0,-2)$ divides the segment joining by other two given points in the ratio $3:2$ internally.

• A. Statement I is true; Statement II is true; Statement II is a correct explanation for Statement I
• B. Statement I is true; Statement II is true; Statement II is not a correct explanation for Statement I
• C. Statement I is true; Statement II is false
• D. Statement I is false; Statement II is true

Answer 1

Answer: (C)

Let $A(-4,6,10),B(2,4,6)$ and $C(14,0,-2)$ be the given points. Let the point $P$ divides $AB$ in the ratio $k:1$. Then, coordinates of the point $P$ are
$\frac{2k-4}{k+1},\frac{4k+6}{k+1},\frac{6k+10}{k+1}$
Let us examine whether for some value of $k$, the point $P$ coincides with point $C$.
On putting $\frac{2k-4}{k+1}=14$, we get $k=-\frac{3}{2}$
When $k=-\frac{3}{2}$, then $\frac{4k+6}{k+1}=\frac{4\left(-\frac{3}{2}\right)+6}{-\frac{3}{2}+1}=0$
and $\frac{6k+10}{k+1}=\frac{6\left(-\frac{3}{2}\right)+10}{-\frac{3}{2}+1}=-2$
Therefore, $C(14,0,-2)$ is a point which divides $AB$ externally in the ratio $3:2$ and is same as $P$. Hence, $A,B,C$ are collinear.