Statement I Let A= a, b and B= a, b, c . Then, A not ⊂ B Statement II If A ⊂ B, then A ∪ B=B.

Question

Statement I Let A= a, b and B= a, b, c . Then, A not ⊂ B Statement II If A ⊂ B, then A ∪ B=B. (A) Statement I is true (B) Statement II is true (C) Both are true (D) Both are false

Tardigrade Admin · Accepted Answer

A= a, b B= a, b, c Since, all the elements of A are in B. So, A ⊂ B Hence, Statement I is false. ∵ A ⊂ B ⇒ A ∪ B=B Therefore, Statement II is true.

Q. Statement I Let $A = {a, b}$ and $B = {a, b, c}$ . Then, $A \neq \subset B$
Statement II If $A \subset B$ , then $A \cup B = B$ .

Statement I is true

Statement II is true

Both are true

Both are false

$A = {a, b}, B = {a, b, c}$
Since, all the elements of $A$ are in $B$ . So,
$A \subset B$
Hence, Statement I is false.
$∵ A \subset B$
$\Rightarrow A \cup B = B$
Therefore, Statement II is true.

Q. Statement I Let A={a,b} and B={a,b,c}. Then, A⊂B Statement II If A⊂B, then A∪B=B.