Statement I:In the relation f=(1/2l)√(T/m), where symbols have standard meaning, m represent linear mass density Statement II: frequency has the dimensions of inverse of time.

Question

Statement I:In the relation f=(1/2l)√(T/m), where symbols have standard meaning, m represent linear mass density Statement II: frequency has the dimensions of inverse of time. (A) If both statement I and statement II are true and statement II is the correct explanation of statement I. (B) If both statement I and statement II are true but statement II is not the correct explanation of statement I. (C) If statement I is true but statement II is false. (D) If both statement I and statement II are false

Tardigrade Admin · Accepted Answer

From, f=(1/2l)√(T/m),f2=(T/4l2m) or m=(T/4l2f2)=([MLT-2]/L2T-2) =(M/L)=( textMass/ textLength)= linear mass density

Q. Statement I:In the relation $f = \frac{1}{2 l} \frac{T}{m},$ where symbols have standard meaning, $m$ represent linear mass density
Statement II: frequency has the dimensions of inverse of time.

If both statement I and statement II are true and statement II is the correct explanation of statement I.

If both statement I and statement II are true but statement II is not the correct explanation of statement I.

If statement I is true but statement II is false.

If both statement I and statement II are false

From, $f = \frac{1}{2 l} \frac{T}{m}, f^{2} = \frac{T}{4 l ^{2} m}$

or $m = \frac{T}{4 l ^{2} f ^{2}} = \frac{[ M L T ^{- 2} ]}{L ^{2} T ^{- 2}}$
$= \frac{M}{L} = \frac{Mass}{Length} =$ linear mass density

Q. Statement I:In the relation f=2l1​mT​,​ where symbols have standard meaning, m represent linear mass density Statement II: frequency has the dimensions of inverse of time.