Statement-I: If -5 le 2x + 9

Question

Statement-I: If -5 le 2x + 9 < 2, then x ∈ [-7, -3.5] Statement-II: The graphical representation of - 5<2x + 9 le 2 is<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/5ae0c6b0fe1bfac576d398bd7e744455-.jpeg" /> (A) If both Statement-I and Statement-II are true and Statement-II is the correct explanation of Statement-I (B) If both Statement-I and Statement-II are true but Statement-II is not the correct explanation of Statement-I (C) If Statement-I is true but Statement-II is false (D) If Statement-I is false and Statement-II is true

Tardigrade Admin · Accepted Answer

We have, - 5<2x + 9 le 2 ⇒ - 1 4 le 2 x < -7 ⇒ -7 le x le (-7/2) ∴ x∈[-7, (-7/2)]

Q. Statement-I: If $- 5 \leq 2 x + 9 < 2$ , then $x \in [- 7, - 3.5]$
Statement-II: The graphical representation of
$- 5 < 2 x + 9 \leq 2$ is

If both Statement-I and Statement-II are true and Statement-II is the correct explanation of Statement-I

If both Statement-I and Statement-II are true but Statement-II is not the correct explanation of Statement-I

If Statement-I is true but Statement-II is false

If Statement-I is false and Statement-II is true

We have, $- 5 < 2 x + 9 \leq 2 \Rightarrow - 14 \leq 2 x < - 7$
$\Rightarrow - 7 \leq x \leq \frac{- 7}{2} ∴ x \in [- 7, \frac{- 7}{2}]$

Q. Statement-I: If −5≤2x+9<2, then x∈[−7,−3.5] Statement-II: The graphical representation of −5<2x+9≤2 is